 Get Sketch The Region Enclosed By The Given Curves. Y = Sec2(X), Y = 8 Cos(X), −Π/3 ≤ X ≤ Π/3 Background

# Get Sketch The Region Enclosed By The Given Curves. Y = Sec2(X), Y = 8 Cos(X), −Π/3 ≤ X ≤ Π/3 Background

Use the method of cylindrical shells to write down the integral to represent the volume generated write down the integral to express the area of the surface obtained by rotating the curve about the given axis.

Get Sketch The Region Enclosed By The Given Curves. Y = Sec2(X), Y = 8 Cos(X), −Π/3 ≤ X ≤ Π/3 Background. Sketch the region enclosed by the given decide whether to integrate with respect to x or y. The curves enclose about 10 unit squares, so that matches the above result. Sharp Recovery Bounds For Convex Demixing With Applications Arxiv Vanity from media.arxiv-vanity.com Y = sec2x, y = 8 cos x, −π/3 ≤ x ≤ π/3. We can extend the notion of the area under a curve and consider the area of the region between two curves. I sort of get that the x axis represents 'cos' and the y axis represents 'sin', but what about tan?

### The curves enclose about 10 unit squares, so that matches the above result.

2 (a) (i) sketch the graph of y = x cos x, for 0 ≤ x ≤ 2 making clear the approximate positions of the 2 (b) solve the equation 2 cos x + sin x = 2 for x in the interval 0 ≤ x ≤ π , giving your answers exactly. We welcome your feedback, comments and questions about this site or page. Cos(x) is above sin(2x) from 0 to pi/6. This problem has been solved!